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// David Eberly, Geometric Tools, Redmond WA 98052
// Copyright (c) 1998-2021
// Distributed under the Boost Software License, Version 1.0.
// https://www.boost.org/LICENSE_1_0.txt
// https://www.geometrictools.com/License/Boost/LICENSE_1_0.txt
// Version: 4.0.2019.08.13
#pragma once
#include <Mathematics/FIQuery.h>
#include <Mathematics/TIQuery.h>
#include <Mathematics/Hypersphere.h>
#include <Mathematics/Vector2.h>
namespace gte
{
template <typename Real>
class TIQuery<Real, Circle2<Real>, Circle2<Real>>
{
public:
struct Result
{
bool intersect;
};
Result operator()(Circle2<Real> const& circle0, Circle2<Real> const& circle1)
{
Result result;
Vector2<Real> diff = circle0.center - circle1.center;
result.intersect = (Length(diff) <= circle0.radius + circle1.radius);
return result;
}
};
template <typename Real>
class FIQuery<Real, Circle2<Real>, Circle2<Real>>
{
public:
struct Result
{
bool intersect;
// The number of intersections is 0, 1, 2 or maxInt =
// std::numeric_limits<int>::max(). When 1, the circles are
// tangent and intersect in a single point. When 2, circles have
// two transverse intersection points. When maxInt, the circles
// are the same.
int numIntersections;
// Valid only when numIntersections = 1 or 2.
Vector2<Real> point[2];
// Valid only when numIntersections = maxInt.
Circle2<Real> circle;
};
Result operator()(Circle2<Real> const& circle0, Circle2<Real> const& circle1)
{
// The two circles are |X-C0| = R0 and |X-C1| = R1. Define
// U = C1 - C0 and V = Perp(U) where Perp(x,y) = (y,-x). Note
// that Dot(U,V) = 0 and |V|^2 = |U|^2. The intersection points X
// can be written in the form X = C0+s*U+t*V and
// X = C1+(s-1)*U+t*V. Squaring the circle equations and
// substituting these formulas into them yields
// R0^2 = (s^2 + t^2)*|U|^2
// R1^2 = ((s-1)^2 + t^2)*|U|^2.
// Subtracting and solving for s yields
// s = ((R0^2-R1^2)/|U|^2 + 1)/2
// Then replace in the first equation and solve for t^2
// t^2 = (R0^2/|U|^2) - s^2.
// In order for there to be solutions, the right-hand side must be
// nonnegative. Some algebra leads to the condition for existence
// of solutions,
// (|U|^2 - (R0+R1)^2)*(|U|^2 - (R0-R1)^2) <= 0.
// This reduces to
// |R0-R1| <= |U| <= |R0+R1|.
// If |U| = |R0-R1|, then the circles are side-by-side and just
// tangent. If |U| = |R0+R1|, then the circles are nested and
// just tangent. If |R0-R1| < |U| < |R0+R1|, then the two circles
// to intersect in two points.
Result result;
Vector2<Real> U = circle1.center - circle0.center;
Real USqrLen = Dot(U, U);
Real R0 = circle0.radius, R1 = circle1.radius;
Real R0mR1 = R0 - R1;
if (USqrLen == (Real)0 && R0mR1 == (Real)0)
{
// Circles are the same.
result.intersect = true;
result.numIntersections = std::numeric_limits<int>::max();
result.circle = circle0;
return result;
}
Real R0mR1Sqr = R0mR1 * R0mR1;
if (USqrLen < R0mR1Sqr)
{
// The circles do not intersect.
result.intersect = false;
result.numIntersections = 0;
return result;
}
Real R0pR1 = R0 + R1;
Real R0pR1Sqr = R0pR1 * R0pR1;
if (USqrLen > R0pR1Sqr)
{
// The circles do not intersect.
result.intersect = false;
result.numIntersections = 0;
return result;
}
if (USqrLen < R0pR1Sqr)
{
if (R0mR1Sqr < USqrLen)
{
Real invUSqrLen = (Real)1 / USqrLen;
Real s = (Real)0.5 * ((R0 * R0 - R1 * R1) * invUSqrLen + (Real)1);
Vector2<Real> tmp = circle0.center + s * U;
// In theory, discr is nonnegative. However, numerical round-off
// errors can make it slightly negative. Clamp it to zero.
Real discr = R0 * R0 * invUSqrLen - s * s;
if (discr < (Real)0)
{
discr = (Real)0;
}
Real t = std::sqrt(discr);
Vector2<Real> V{ U[1], -U[0] };
result.point[0] = tmp - t * V;
result.point[1] = tmp + t * V;
result.numIntersections = (t > (Real)0 ? 2 : 1);
}
else
{
// |U| = |R0-R1|, circles are tangent.
result.numIntersections = 1;
result.point[0] = circle0.center + (R0 / R0mR1) * U;
}
}
else
{
// |U| = |R0+R1|, circles are tangent.
result.numIntersections = 1;
result.point[0] = circle0.center + (R0 / R0pR1) * U;
}
// The circles intersect in 1 or 2 points.
result.intersect = true;
return result;
}
};
}