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56 lines
1.6 KiB
56 lines
1.6 KiB
#include <iostream>
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#include <ginac/ginac.h>
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#include <chrono>
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using namespace std;
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using namespace GiNaC;
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vector<ex> factor_parser(ex f){
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vector<ex> ans;
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int cnt=0;
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string cur="";
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return ans;
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}
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int main() {
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symbol s("s");
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symbol t("t"); // Declare a GiNaC symbol 'x'
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symtab table;
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table["s"] = s;
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table["t"] = t;
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parser reader(table);
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ex e=reader("4*s^4 + s^2*t^2 + s^2 + 6*t");
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matrix A(17,17);
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for(int i=0;i<17;i++)
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for(int j=0;j<17;j++)
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A(i,j)=rand()%5-2;
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// cout<<determinant(A)<<endl;
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lst t1={s==0.1,t==0.1};
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double sss=ex_to<numeric>(subs(e,t1)).to_double();
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cout<<sss<<endl;
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// cout<<ex_to<double>(subs(e,t1))<<endl;
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// 获取当前时间点，作为程序开始运行的时间
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// auto start_time = std::chrono::high_resolution_clock::now();
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// // 模拟程序运行，这里用一个简单的循环做示例
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// for (int i = 0; i < 10000000; ++i) {
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// // do something
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// }
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// // 获取当前时间点，作为程序结束运行的时间
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// auto end_time = std::chrono::high_resolution_clock::now();
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// // 计算程序运行时间
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// auto duration = std::chrono::duration_cast<std::chrono::milliseconds>(end_time - start_time);
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// // 输出程序运行时间（以秒为单位）
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// std::cout << "程序运行时间：" << duration.count() << " 秒" << std::endl;
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// return 0;
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// cout<<e<<endl;
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// ex curh=quo(e,s*s+4*s-4,s);
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// ex r=rem(e,s*s+4*s-4,s);
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// cout<<e<<endl;
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// cout<<r<<endl;
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// curh=expand(curh);
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// cout<<curh<<endl;
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}
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