- penalty_par_intersection 100 或 400 结果差不多

- 注释penalty_par_distance=8 的intersection_distance截断可以跑多线缆，否则只有单线缆
- 不判断求交效果比较好

include/Const.h

@@ -155,13 +155,13 @@ inline double distan(P A, P B, int inOut1, int inOut2)
 			penalty_par_intersection = 1;
 		else
 			penalty_par_intersection = 100; //*原400
-		cout << "out: len:" << len << " intersection_distance" << intersection_distance << endl;
+		// cout << "out: len:" << len << " intersection_distance" << intersection_distance << endl;
 		//----------------------mark-----------------------//
 		// 注释下面效果可能好
-		if (len > intersection_distance)
+		// if (len > intersection_distance)
-			penalty_par_distance = 8;
+		// 	penalty_par_distance = 8;
-		else
+		// else
-			penalty_par_distance = 1;
+		// 	penalty_par_distance = 1;
 	}
 
 	double len1 = sqrt((A.y - Ycenter) * (A.y - Ycenter) + (A.z - Zcenter) * (A.z - Zcenter));
@@ -237,7 +237,7 @@ inline double distan(P A, P B)
 			penalty_par_intersection = 1;
 		else
 			penalty_par_intersection = 100; //*原400
-		cout << "no_out: len:" << len << " intersection_distance" << intersection_distance << endl;
+		// cout << "no_out: len:" << len << " intersection_distance" << intersection_distance << endl;
 		if (len > intersection_distance)
 			penalty_par_distance = 8;
 		else